Determine the mass of solid NaCH₂COO that must be dissolved in an existing 500.0 mL solution of 0.200 M CH₂COOH to form

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Determine the mass of solid NaCH₂COO that must be dissolved in an existing 500.0 mL solution of 0.200 M CH₂COOH to form

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Determine The Mass Of Solid Nach Coo That Must Be Dissolved In An Existing 500 0 Ml Solution Of 0 200 M Ch Cooh To Form 1
Determine The Mass Of Solid Nach Coo That Must Be Dissolved In An Existing 500 0 Ml Solution Of 0 200 M Ch Cooh To Form 1 (219.4 KiB) Viewed 9 times
Determine the mass of solid NaCH₂COO that must be dissolved in an existing 500.0 mL solution of 0.200 M CH₂COOH to form a buffer with a pH equal to 5.00. The value of Ka for CH₂COOH is 1.8 × 105. NEXT Let x represent the original concentration of CH₂COO in the water. Based on the given values, set up the ICE table in order to determine the unknown. Initial (M) Change (M) Equilibrium (M) 1.0 x 10° x+1.0 x 10 0 CH₂COOH(aq) + -1.0 × 10⁰ 1 x-1.0 x 10° 1.8 × 10⁰ x + 1.8 x 10° 0.200 H₂O(l) -1.8 × 10⁰ 2 x-1.8 x 10 5.00 x + 5.00 H,O*(aq) + CH₂COO (aq) -5.00 3 x - 5.00 1.0 x 10⁰ x + 1.0 × 10° RESET -1.0 x 10⁰ x-1.0 x 10°

Determine the mass of solid NaCH COO that must be dissolved in an existing 3 500.0 mL solution of 0.200 M CH₂COOH to form a buffer with a pH equal to 5.00. The value of Ka for CH₂COOH is 1.8 × 105. < PREV NEXT > Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. [0] [x - 5.00] [500.0] [x + 1.0 × 10⁹] 1 Ka = [0.200] [x - 1.0 × 10⁹] [5.00] [x + 1.0 × 105] 2 [1.0 × 10⁹] [x - 1.0 × 105] 3 = 1.8 × 10-5 [1.0 × 105] [x + 1.8 × 105] [1.8 × 10%] [x - 1.8 × 105] RESET [x+ 5.00]

Determine the mass of solid NACH COO that must be dissolved in an existing 3 500.0 mL solution of 0.200 M CH₂COOH to form a buffer with a pH equal to 5.00. 3 The value of Ka for CH₂COOH is 1.8 × 10¹5. PREV 0 3.6 × 10³ Based on your ICE table and Ka expression, determine the original mass of solid NaCH COO dissolved. 0.360 1 5.9 × 105 30 MNACH₂COO 4.3 × 105 2 21 = 43 g 3 11 15 RESET 59
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