1. Given the following Kp values at 25°C: C (graphite) + ½ O2 (g) CO(g) Kp = 1.13 x 1024 C (graphite) + O2 (g) CO2 (g) K

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answerhappygod
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1. Given the following Kp values at 25°C: C (graphite) + ½ O2 (g) CO(g) Kp = 1.13 x 1024 C (graphite) + O2 (g) CO2 (g) K

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1. Given the following Kp values at 25°C:C (graphite) + ½ O2 (g) CO(g) Kp = 1.13 x 1024C (graphite) + O2 (g) CO2 (g) Kp = 1.25 x 1069
Find Kp for 2 CO (g) + O2 (g) 2 CO2 (g)2. A mixture containing 0.250 mol SbCl3, 0.250 mol Cl2, and 0.500mol SbCl5 comes toequilibrium in a 5.00 liter reaction vessel at 648°C. The reactionisSbCl3 (g) + Cl2 (g) SbCl5 (g)With Kc = 40.0. Determine
a. The direction in which the reaction movesb. The equilibrium concentration of each gas.3. At 850°C, Kp is 14.1 for the reactionC(graphite) + CO2(g) 2CO(g)A reaction vessel at 850°C initially contains CO2 at 0.500 atm, COat 1.00 atm, andgraphite. Determinea. The direction in which the reaction movesb. The equilibrium partial pressure of each gas.4. Consider the reaction Kc = 0.1102 ICI (g) I2 (g) + Cl2(g)A 2.00 – liter vessel initially contains 0.500 mol each of thethree gases. Calculate theequilibrium concentration of ICl.
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