Question 12 Trial #Initial A (M) Initial B (M) Initial Rate (M/s) 1 0.350 0.200 1.20 x 10-5 12 0.350 0.400 1.20 x 10-5 3

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Question 12 Trial #Initial A (M) Initial B (M) Initial Rate (M/s) 1 0.350 0.200 1.20 x 10-5 12 0.350 0.400 1.20 x 10-5 3

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Question 12 Trial Initial A M Initial B M Initial Rate M S 1 0 350 0 200 1 20 X 10 5 12 0 350 0 400 1 20 X 10 5 3 1
Question 12 Trial Initial A M Initial B M Initial Rate M S 1 0 350 0 200 1 20 X 10 5 12 0 350 0 400 1 20 X 10 5 3 1 (49.79 KiB) Viewed 20 times
Question 12 Trial #Initial A (M) Initial B (M) Initial Rate (M/s) 1 0.350 0.200 1.20 x 10-5 12 0.350 0.400 1.20 x 10-5 3 0.700 0.200 2.40 x 10-5 Given the table above, what is the rate law equation? [Select] Rate = [Select] [Select] {A} 1 pts {B}

Question 14 2 A (aq) + 3 B (aq) → 4 C (s) + 5 D (aq) 2 pts In the first 189 s of the given reaction, 0.692 moles of A disappear. In that time period, what is the rate of change in the concentration of B in mol/min?
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