Learning Goal: To understand how to use stoichiometry to convert between quantities of reactants and products in chemica

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

Learning Goal: To understand how to use stoichiometry to convert between quantities of reactants and products in chemica

Post by answerhappygod »

Learning Goal To Understand How To Use Stoichiometry To Convert Between Quantities Of Reactants And Products In Chemica 1
Learning Goal To Understand How To Use Stoichiometry To Convert Between Quantities Of Reactants And Products In Chemica 1 (72.54 KiB) Viewed 11 times
Learning Goal: To understand how to use stoichiometry to convert between quantities of reactants and products in chemical equations. Stoichiometry describes the quantitative relationships among the reactants and products of a balanced reaction by directly comparing mole ratios. Stoichiometry can be used to convert mass, number of moles, or number of particles between products and reactants, as shown in the flowchart displayed in the figure. Substance A Substance B number of particles Avogadro's number 1 I Avogadro's number I number of particles mass moles coefficients from balanced I chemical equation moles mass I molar mass molar I mass How many grams of NH3 can be produced from 2.34 mol of N₂ and excess H₂. Express your answer numerically in grams. ► View Available Hint(s) ΤΕΙ ΑΣΦ Submit Part C IVE | ΑΣΦ = How many grams of H₂ are needed to produce 14.72 g of NH3 ? Express your answer numerically in grams. ► View Available Hint(s) Submit EXX ? + www. g NH3 ? g H₂
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply