A current of 50 A is established in a Cu slab (0.2 cm thick and 2 cm wide). The slab is placed in a magnetic field B of

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answerhappygod
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A current of 50 A is established in a Cu slab (0.2 cm thick and 2 cm wide). The slab is placed in a magnetic field B of

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A current of 50 A is established in a Cu slab (0.2 cm thick and2 cm wide). The slab is placed in a magnetic field B of 1.5 T. Themagnetic field is perpendicular to the plane of the slab and to thecurrent. The free electron concentration in Cu is 8.4×1028/m³. Whatwill be the magnetidue of Hall voltage across the width of theslab?
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