Problem 4: A dragster accelerates from rest down a road of length d = 400.0 m. In the absence of any friction the drag
Posted: Sat Jul 02, 2022 7:37 pm
Problem 4: A dragsteraccelerates from rest down a road of length d =400.0 m. In the absence of any friction the dragster has a constantaccelerationof a = 23 m/s2 in thedirection of motion, and its massis m = 1130 kg. Assume the dragster ismoving in the positive horizontal direction.
Part (a) Assuming there is norolling friction, write an expression for the amount of net workdone on the dragster, Wd, during the run,in terms of the givenquantities. Wd =
Part (b) Now consider the existenceof rolling friction, which causes a total resistive force withmagnitude Fr on the dragster. Writean expression for the work done by this force over adistance d. Wr =
Part (c) Give an expression for thetotal kinetic energy of the dragster, Ed,in the presence of rolling friction after it travels adistance d.
Part (d) What is the dragster'sfinal speed, in meters per second,assuming Fr = 1000 N?
В a bl) g j P Y d h k SF B F₁ i m t 7 89 신 4 5 6 12 3 0 BACKSPACE ( ^^^ / + |VO| VO * DEL HOME END CLEAR
a a g j P В d h k S 0 Fr 1 m t T^^4 + * 7 8 9 ' 5 6 + 12 3 0 HOME VO BACKSPACE END DEL CLEAR
В d h k P e Fr 1 m S a j n t () 7 89 HOME T^^L 4 5 ∞o in N 96m - 6 1 2 3 + 0 NO BACKSPACE DEL + END CLEAR
Part (a) Assuming there is norolling friction, write an expression for the amount of net workdone on the dragster, Wd, during the run,in terms of the givenquantities. Wd =
- Problem 4 A Dragster Accelerates From Rest Down A Road Of Length D 400 0 M In The Absence Of Any Friction The Drag 1 (6.43 KiB) Viewed 38 times
- Problem 4 A Dragster Accelerates From Rest Down A Road Of Length D 400 0 M In The Absence Of Any Friction The Drag 2 (6.52 KiB) Viewed 38 times
- Problem 4 A Dragster Accelerates From Rest Down A Road Of Length D 400 0 M In The Absence Of Any Friction The Drag 3 (7 KiB) Viewed 38 times
В a bl) g j P Y d h k SF B F₁ i m t 7 89 신 4 5 6 12 3 0 BACKSPACE ( ^^^ / + |VO| VO * DEL HOME END CLEAR
a a g j P В d h k S 0 Fr 1 m t T^^4 + * 7 8 9 ' 5 6 + 12 3 0 HOME VO BACKSPACE END DEL CLEAR
В d h k P e Fr 1 m S a j n t () 7 89 HOME T^^L 4 5 ∞o in N 96m - 6 1 2 3 + 0 NO BACKSPACE DEL + END CLEAR