Problem 4: A dragster accelerates from rest down a road of length d = 400.0 m. In the absence of any friction the drag

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Problem 4: A dragster accelerates from rest down a road of length d = 400.0 m. In the absence of any friction the drag

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Problem 4: A dragsteraccelerates from rest down a road of length d =400.0 m. In the absence of any friction the dragster has a constantaccelerationof a = 23 m/s2 in thedirection of motion, and its massis m = 1130 kg. Assume the dragster ismoving in the positive horizontal direction.
Part (a) Assuming there is norolling friction, write an expression for the amount of net workdone on the dragster, Wd, during the run,in terms of the givenquantities. Wd =
Problem 4 A Dragster Accelerates From Rest Down A Road Of Length D 400 0 M In The Absence Of Any Friction The Drag 1
Problem 4 A Dragster Accelerates From Rest Down A Road Of Length D 400 0 M In The Absence Of Any Friction The Drag 1 (6.43 KiB) Viewed 36 times
Part (b) Now consider the existenceof rolling friction, which causes a total resistive force withmagnitude Fr on the dragster. Writean expression for the work done by this force over adistance d. Wr =
Problem 4 A Dragster Accelerates From Rest Down A Road Of Length D 400 0 M In The Absence Of Any Friction The Drag 2
Problem 4 A Dragster Accelerates From Rest Down A Road Of Length D 400 0 M In The Absence Of Any Friction The Drag 2 (6.52 KiB) Viewed 36 times
Part (c) Give an expression for thetotal kinetic energy of the dragster, Ed,in the presence of rolling friction after it travels adistance d.
Problem 4 A Dragster Accelerates From Rest Down A Road Of Length D 400 0 M In The Absence Of Any Friction The Drag 3
Problem 4 A Dragster Accelerates From Rest Down A Road Of Length D 400 0 M In The Absence Of Any Friction The Drag 3 (7 KiB) Viewed 36 times
Part (d) What is the dragster'sfinal speed, in meters per second,assuming Fr = 1000 N?
В a bl) g j P Y d h k SF B F₁ i m t 7 89 신 4 5 6 12 3 0 BACKSPACE ( ^^^ / + |VO| VO * DEL HOME END CLEAR

a a g j P В d h k S 0 Fr 1 m t T^^4 + * 7 8 9 ' 5 6 + 12 3 0 HOME VO BACKSPACE END DEL CLEAR

В d h k P e Fr 1 m S a j n t () 7 89 HOME T^^L 4 5 ∞o in N 96m - 6 1 2 3 + 0 NO BACKSPACE DEL + END CLEAR
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