v=0.855 m/s length=0.65m 0.359

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answerhappygod
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v=0.855 m/s length=0.65m 0.359

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v=0.855 m/s
length=0.65m
0.359
V 0 855 M S Length 0 65m 0 359 1
V 0 855 M S Length 0 65m 0 359 1 (17.96 KiB) Viewed 55 times
V 0 855 M S Length 0 65m 0 359 2
V 0 855 M S Length 0 65m 0 359 2 (17.96 KiB) Viewed 55 times
A man pushing a crate of mass m- 92.0 kg at a speed of v=0.555 m/s encounters a rough horizontal surface of length = 0.65 m as in the figure below. If the coefficient of kinetic friction between the crate and rough surface is 0.359 and he exerts a constant hortzontal force of 284 N on the crate D (a) Find the magnitude and direction of the net force on the crate while it is on the rough surface. magnitude 40.0 N direction opposite as the motion of the crate (b) Find the net work done on the crate while it is on the rough surface. -26 J (c) Find the speed of the crate when it reaches the end of the rough surface. 1:29 x Your response differs from the correct answer by more than 100%. m/s Need Help? Read Wichit
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