Problem 06.018-Method of joints, average difficulty The truss shown is one of several supporting an advertising panel. D

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Problem 06 018 Method Of Joints Average Difficulty The Truss Shown Is One Of Several Supporting An Advertising Panel D 1 (28.94 KiB) Viewed 56 times

Problem 06.018-Method of joints, average difficulty The truss shown is one of several supporting an advertising panel. Determine the force in each member of the truss for a wind load of P=920 N. (Round the final answers to the nearest whole number.) P. 3.75 m P A 3,75 m 1--2---2- The force in member BD (FBD) is [ The force in member DE (FDE) is The force in member AB (FAB) is [ The force in member AC (FAC is) The force in member CF(FCA) is [ The force in member EF (FEA) is [ The force in member CE (FCE) is) The force in member BC (Fad is The force in member BE (FBB) is N. (Compression) IN. (Tension) N. (Compression) N. (Tension) N. (Tension) N. (Tension) N. (Compression) N. (Tension) N. (Compression)