solve the problem if complete solution and answer I give you thump up this is example

Post by **answerhappygod** » Fri Jul 01, 2022 7:09 am

solve the problem if complete solution and answer I give you thump up

: Solve The Problem If Complete Solution And Answer I Give You Thump Up This Is Example 1 (23.42 KiB) Viewed 25 times

this is example

: Solve The Problem If Complete Solution And Answer I Give You Thump Up This Is Example 2 (29.91 KiB) Viewed 25 times

: Solve The Problem If Complete Solution And Answer I Give You Thump Up This Is Example 3 (38.49 KiB) Viewed 25 times

: Solve The Problem If Complete Solution And Answer I Give You Thump Up This Is Example 4 (47.5 KiB) Viewed 25 times

Determine the smallest cross-sectional area A required for the members of the truss shown, so that the horizontal deflection at joint D does not exceed 10 mm. 50 kN 100 KN 50 KN 15 A 3m. EA = constant E=70 GPa D B 4 m
MA=0 Byx3=50x3+ 100 x4 By = 188-3 KN Fy=0 so + 50 = By + Ay 100 = 183-33+ Ay Ay = -83-33KN Ay = 83.33KN (+) Joint A FAB = 100KN (T) FAC = 83.33 KN (T) Jount B Fx = 0 100+ FBC COS 53-1=0 FBC = -166-55KN = 166.55KN (C) Fy=0 18 3:33+ FBD + FBcsin (3.1=0 183.33+ FBD-166-55 sin 53-1=0 FBD-50-14 KN = 50.14 KN [comp] 100 lOOKN 100 50 FBC 100 -3m- D FAC L 82-83 50 4m 79) By FAB FBD T183-3
Joint D FDC = OKN K-tore:- MA O Byx3=4 By = 4/3 (1) Ay = 4/3 (4) Ax = 1 (←) Joint A FAC = 4/3 (1) FAB = 1 (T) Joint c Fy=0 +FBc Sin 53-1=0 FBC = -1.66 FBC = 1.66(C) Fx=0 FCD + FacCOs 53-1=0 FCD = 1 (T) Fos=0 Ax ← FDC A Ayk-3m- V4/3 D P53.1 4/3 FBC D 4m 8V FAB Feo
Joint A FAC = 4/3 (1) FAB = 1 (T) Joint c Fy=0 +FBc Sin 53-1=0 FBC = -1.66 FBC = 1.66(C) Fx=0 Fco + FBcCOs 53-1=0 FCD = 1 (T) FOB = 0 Member AB AC BD SO P 100 83.33 166.55 50.14 0 дос ерки AE 10=41-24×108 Ax70x10³ A = 3084 mm² K 1 4/3 1.66 0 1 J 8000 4000 5000 4000 55 MEAU A V43 4/3 53.1 FBC PKL 3x108 4-44x 108 18.6 x 108 O 3000 ≤PKL = 21:24X108 Foo