(c) By relating derivatives of To to those of , and dividing every term in the mo- mentum equation by U. we can argue th

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(c) By relating derivatives of To to those of , and dividing every term in the mo- mentum equation by U. we can argue th

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C By Relating Derivatives Of To To Those Of And Dividing Every Term In The Mo Mentum Equation By U We Can Argue Th 1
C By Relating Derivatives Of To To Those Of And Dividing Every Term In The Mo Mentum Equation By U We Can Argue Th 1 (32.51 KiB) Viewed 52 times
(c) By relating derivatives of To to those of , and dividing every term in the mo- mentum equation by U. we can argue that and u/U both satisfy the same differential equation and the same boundary conditions. Consequently, we can write 0 u/U amd hence, by re-arrangement, U To = Tw+7 (7 (6) This also allows us to determine the static temperature, since in a boundary layer with u²v², we can write T = To-u²/(20p). -(To,00 - Tw). (d) Using all the information above, and the expression qu = -k(T/ay)ly-o, express the wall heat flux in terms of the velocity gradient at the wall, and hence the wall shear stress (T) asssuming a Newtonian fluid.
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