(a) (b) (c) A current distribution produces a magnetic flux density, B = (-6xz + 4x²y + 3xz²)ax + (y + 6yz - 4xy²)ay + (

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(a) (b) (c) A current distribution produces a magnetic flux density, B = (-6xz + 4x²y + 3xz²)ax + (y + 6yz - 4xy²)ay + (

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A B C A Current Distribution Produces A Magnetic Flux Density B 6xz 4x Y 3xz Ax Y 6yz 4xy Ay 1
A B C A Current Distribution Produces A Magnetic Flux Density B 6xz 4x Y 3xz Ax Y 6yz 4xy Ay 1 (38.85 KiB) Viewed 23 times
(a) (b) (c) A current distribution produces a magnetic flux density, B = (-6xz + 4x²y + 3xz²)ax + (y + 6yz - 4xy²)ay + (y² - z³ - 2x²-z)a₂ Wb/m². Calculate magnetic flux through the surface defined by y = 1,0 ≤ x,z ≤ 2. [5 Marks] [C01, PO1, C3] An infinitely long filamentary wire carries a current of 5 A in the z-direction. Calculate the magnetic flux through the square loop described by 1 ≤p≤6 m and 0.1 ≤z ≤2.1 m. A current distribution gives rise to the vector magnetic potential A = 2y²z ax + xy² ay - 6xyz a, Wb/m. (i) [5 Marks] [CO1, PO1, C3] Compute the magnetic flux density, B Let a loop be described by y = 1 m, 0≤x≤4 m, 0≤z≤5 m. By computing the flux through this loop, show that B. dS = $ A.dl.
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