Please Help!!Part (a): Plot of primary current and secondary current versus time.Part (b): Plot of voltage versus time.

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Please Help!!Part (a): Plot of primary current and secondary current versus time.Part (b): Plot of voltage versus time.

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Please Help!!Part (a): Plot of primary current and secondary current versus time.Part (b): Plot of voltage versus time. Plot of power (voltage x current) versus time.
Please Help!!
Part (a): Plot of primary current and secondary current versus time.Part (b): Plot of voltage versus time. Plot of power (voltage x current) versus time.
Please Help Part A Plot Of Primary Current And Secondary Current Versus Time Part B Plot Of Voltage Versus Time 1
Please Help Part A Plot Of Primary Current And Secondary Current Versus Time Part B Plot Of Voltage Versus Time 1 (23.91 KiB) Viewed 38 times
Please Help Part A Plot Of Primary Current And Secondary Current Versus Time Part B Plot Of Voltage Versus Time 2
Please Help Part A Plot Of Primary Current And Secondary Current Versus Time Part B Plot Of Voltage Versus Time 2 (21.74 KiB) Viewed 38 times
56. A transformer whose nameplate reads 2300/230 V, 25 KVA operates with primary and secondary voltages of 2300 V and 230 V rms, respectively, and can supply 25 KVA from its secondary winding. If this transformer is supplied with 2300 V rms and is connected to secondary loads requiring 8 kW at unity PF and 15 kVA at 0.8 PF lagging, (a) what is the primary current? (b) How many kilowatts can the transformer still supply to a load operating at 0.95 PF lagging? (c) Verify your answers with PSpice.
Lonel Ofte 8 ay 130 Lond!! 15 KVA al 0.2pt legging Jig= 136 Comuned load (Standing our) - (04) 61.111-3360 = ₁ + = 34.31166an (-2636 T₁=965 (-24.112 A porary cure y VA 136 9635 1306 Vr pronary cred = 1.05 Kun supplied only PUA = 31.92 UA 25= √2.45+ AU √26²-11 When so comment on additional load, babat null bring suppled fountamer should not making of the Thus D5= √KUFA = KUAL = 9.05 A ruf Adde kun that con be supplied PER A cually being suppled Alinat e pover that a tendens till 10* 15-25 Kung =√√²-3195 = 12 ND Additonal to that can be supplied by thenplomer DINA still can supply at one of ligging calle be 6 Additional para tusfoor) - = 1 cad = (ANA) (0.95 ing) = 11.4 KM
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