1.4. Exercise Questions and Problems 1.4.1 What is the advantage of correction power factor? 1.4.2 Name and explain two

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1 4 Exercise Questions And Problems 1 4 1 What Is The Advantage Of Correction Power Factor 1 4 2 Name And Explain Two 1 (216.76 KiB) Viewed 36 times

1.4. Exercise Questions and Problems 1.4.1 What is the advantage of correction power factor? 1.4.2 Name and explain two methods used for power factor correction? 1.4.3 What is the advantage of three phase system over single phase system? 1.4.4 Two impedances, Z1 = 0.8 +j5.692 and Z2 = 8 - j16 2, and a single phase motor are connected in parallel across a 200-V rms, 60-Hz supply as shown in Figure. The motor draws 5 kVA at 0.8 power factor lagging. + I 200/0° V 0.8 j5.6 -j16 12 I 13 M 3 S3 = 5 kVA at 0.8 PF lag a) Find the complex power S1, S2 for the two impedances, and S3 for the motor. b) Determined the total appearance power taking from the supply, the supply current and overall power factor. c) A capacitor is connected in parallel with loads. Find the Kvar and the capacitor in µF to improve the overall power factor to unity. What is the new line current? R 60