Name: (11) The supply voltage VCC equals 9V. The base resistor RB is 42k0 Take 0.6V for the knee voltage of the base-emi

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answerhappygod
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Name: (11) The supply voltage VCC equals 9V. The base resistor RB is 42k0 Take 0.6V for the knee voltage of the base-emi

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Name 11 The Supply Voltage Vcc Equals 9v The Base Resistor Rb Is 42k0 Take 0 6v For The Knee Voltage Of The Base Emi 1
Name 11 The Supply Voltage Vcc Equals 9v The Base Resistor Rb Is 42k0 Take 0 6v For The Knee Voltage Of The Base Emi 1 (37.92 KiB) Viewed 38 times
Name: (11) The supply voltage VCC equals 9V. The base resistor RB is 42k0 Take 0.6V for the knee voltage of the base-emitter diode. Draw the load line for a short-circuit current of 15mA (a) What is the value of the collector resistor RC in that case? (b) What is then the voltage Vor across the transistor? (c) What is then the current le through the transistor? RB www vcc 9.0V RC Ic (mA) 15 10 Student nr. n saturation region 5 Answers: (a) RC- (12) Same circuit and transistor as above, but now with a short- scircuit current of 5 mA. Draw the new load line. (a) What is the value of the collector resistor RC in that case? (b) What is then the voltage Va across the transistor? (c) What is then the current le through the transistor? (b) Va (c) k active region cutoff region 10 15 VCE (V) {npn) 20 Answers: (a) RC = (b) Vc = (c) Ic= 1,-0.4 mA Ig=0.3 mA 1,-0.2 mA 1=0.1mA I=0 mA
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