- Given That O Is The Part Of The Surface Z 2y In The First Octant From X 0 To X 1 If X Y Z Xyz F X Y Z 1 (22.62 KiB) Viewed 33 times
Given that o is the part of the surface z = = 2y in the first octant from x = 0 to x = 1. If (x, y, z) = xyz, F(x, y, z)
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Given that o is the part of the surface z = = 2y in the first octant from x = 0 to x = 1. If (x, y, z) = xyz, F(x, y, z)
Given that o is the part of the surface z = = 2y in the first octant from x = 0 to x = 1. If (x, y, z) = xyz, F(x, y, z) = zi+yj+äk and n is the unit normal vector to the surface pointing outwards, evaluate the following surface integrals: (i) ff (x, y, z) ds. (ii) [f JJF. σ F.ndS. [12 marks]