Answer Happy • Exercise 2. Show that SLn(R) = {AE Mn(R): det A = 1} is a submanifold of Rn of dimension n² - 1.

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Exercise 2. Show that SLn(R) = {AE Mn(R): det A = 1} is a submanifold of Rn of dimension n² - 1.

Posted: Thu Jun 30, 2022 7:39 pm

by answerhappygod

: Exercise 2 Show That Sln R Ae Mn R Det A 1 Is A Submanifold Of Rn Of Dimension N 1 1 (7.32 KiB) Viewed 34 times

Exercise 2. Show that SLn(R) = {AE Mn(R): det A = 1} is a submanifold of Rn of dimension n² - 1.