Exercise 2. Show that SLn(R) = {AE Mn(R): det A = 1} is a submanifold of Rn of dimension n² - 1.

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Exercise 2. Show that SLn(R) = {AE Mn(R): det A = 1} is a submanifold of Rn of dimension n² - 1.

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Exercise 2 Show That Sln R Ae Mn R Det A 1 Is A Submanifold Of Rn Of Dimension N 1 1
Exercise 2 Show That Sln R Ae Mn R Det A 1 Is A Submanifold Of Rn Of Dimension N 1 1 (7.32 KiB) Viewed 32 times
Exercise 2. Show that SLn(R) = {AE Mn(R): det A = 1} is a submanifold of Rn of dimension n² - 1.
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