Consider a differential equation Prove that ay" + (1+x)y' +y = 0.y(0) = 1, y(1) = 1. 6 3²2(x) = (1 + x)² for the outer s

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answerhappygod
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Consider a differential equation Prove that ay" + (1+x)y' +y = 0.y(0) = 1, y(1) = 1. 6 3²2(x) = (1 + x)² for the outer s

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Consider A Differential Equation Prove That Ay 1 X Y Y 0 Y 0 1 Y 1 1 6 3 2 X 1 X For The Outer S 1
Consider A Differential Equation Prove That Ay 1 X Y Y 0 Y 0 1 Y 1 1 6 3 2 X 1 X For The Outer S 1 (17.48 KiB) Viewed 46 times
Consider a differential equation Prove that ay" + (1+x)y' +y = 0.y(0) = 1, y(1) = 1. 6 3²2(x) = (1 + x)² for the outer solution and, (1+x)³ 2(1+x)³ 4(1+x) X₁(x) = -x + A₁ (-¹x²¹6x + x) + A₁(e¯* − 1), Ao and X₂(X) = x² − 2X + A₂ (²√x+6−x − x² + 2x) + A₁ (−½X²8¯× + x) + A₂ (e¯* − 1), for the inner solution.
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