- Let R T 7 Tan T I 3 Cos 3t J And To 0 A Find The Value Of R T At To Give Your Answer Using Component For 1 (41.64 KiB) Viewed 33 times
For the vector function r(t) = 4 sin ( ¾ät)i + 3j − 7tªk at to = 1. (a) Find the value of r(t) at to. (Give your answer using component form or standard basis vectors. Express numbers in exact form. Use symbolic notation and fractions where needed.) r(to) = (b) Find the limit of r(t) as t → to. ((Give your answer using component form or standard basis vectors. Express numbers in exact form. Use symbolic notation and fractions where needed.) lim r(t) = 1-10 (c) Determine whether r is continuous at to. r is not continuous at to. r is continuous at to.
Determine where the vector function r(t) = ln (5t)i + e−³¹ j is continuous. (Give your answer as an interval in the form (*, *). Use the symbol co for infinity, U for combining intervals, and an appropriate type of parenthesis "(",")", "[","]" depending on whether the interval is open or closed. Enter Ø if the interval is empty. Express numbers in exact form. Use symbolic notation and fractions where needed.) t E
Find the domain of the vector function r(t) = 57²i + 7j − 3tk. (Use symbolic notation and fractions where needed. Give your answers as intervals in the form (*, *). Use the symbol ∞ for infinity, U for combining intervals, and an appropriate type of parenthesis "(", ")", "[" or "]" depending on whether the interval is open or closed. Enter Ø if the interval is empty.) D(r(t)) =