5. Given that is the part of the surface z = 2-y in the first octant from z = 0 to z = 1. If (x, y, z) = xyz, F(x, y, z)

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5. Given that is the part of the surface z = 2-y in the first octant from z = 0 to z = 1. If (x, y, z) = xyz, F(x, y, z)

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5 Given That Is The Part Of The Surface Z 2 Y In The First Octant From Z 0 To Z 1 If X Y Z Xyz F X Y Z 1
5 Given That Is The Part Of The Surface Z 2 Y In The First Octant From Z 0 To Z 1 If X Y Z Xyz F X Y Z 1 (11.3 KiB) Viewed 26 times
5. Given that is the part of the surface z = 2-y in the first octant from z = 0 to z = 1. If (x, y, z) = xyz, F(x, y, z)=zi+yj+rk and n is the unit normal vector to the surface pointing outwards, evaluate the following surface integrals: (i) f(x, y, 2) ds. (ii) [fF.n F.ndS. [12 marks]
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