Question 1 (1 point) Given the following balanced equation: 2 KHCO₂ (s) K₂CO₂ (s) + H₂CO₂(e) Molar mass of KHCO, is 100.

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Question 1 1 Point Given The Following Balanced Equation 2 Khco S K Co S H Co E Molar Mass Of Khco Is 100 1 (26.87 KiB) Viewed 30 times

Question 1 (1 point) Given the following balanced equation: 2 KHCO₂ (s) K₂CO₂ (s) + H₂CO₂(e) Molar mass of KHCO, is 100.12 g Molar mass of K₂CO, is 138.21 g Molar mass of H₂CO is 62.03 g What mass of K₂CO₂ would be produced from 1.976 grams of KHCO3 1.364 g 1.457 01.051 g 0.8407 g Question 2 (1 point) Given the following balanced equation: 2 KHCO₂ (s)--> K₂CO₂ (s) + H₂CO₂(e) Molar mass of KHCO is 100.12 g Molar mass of K₂CO, is 138.21 g Molar mass of H₂CO₂ is 62.03 g What would be the percent yield if 1.370 g of K₂CO3 was produced from 1.976 grams of KHCO₂? O 107 % 106.6 % 100.4 % 096.02 % Question 3 (1 point) Given the following balanced equation 2 KHCO₂ -> K₂CO₂ (s) + H₂CO₂