These types of problems should look extremely familiar to you. Recall that, in some cases, the molecular weight of a com

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These Types Of Problems Should Look Extremely Familiar To You Recall That In Some Cases The Molecular Weight Of A Com 1 (47.98 KiB) Viewed 65 times

These Types Of Problems Should Look Extremely Familiar To You Recall That In Some Cases The Molecular Weight Of A Com 2 (26.86 KiB) Viewed 65 times

These types of problems should look extremely familiar to you. Recall that, in some cases, the molecular weight of a compound will play a role in how you make a solution. In other problems, you may need to use the equation CiVi=C₂V₂ Why does this matter? As you begin to design experiments in the lab, you will have to prepare solutions of varying concentrations from stock and raw materials. Your liquid reagents will come in varying concentrations You may also have to prepare solutions from scratch using dry reagents and a solvent like water. You often will need to serially dilute your stock or prepared solution(s). In order to properly prepare the needed mixture, you will need to make absolutely certain that the stock solution was made with the correct amount of solute in these cases. Helpful tip: The first thing you should do is take note of what you are looking for (or your unknown). For example, if you are trying to figure out how much of a solvent you need to add to a stock solution, then you know you will be looking for volume. This also gives you an indicator of what units should be used in your answer (e.g. L, ml, ul, etc.). Practice: Use the equation C₁V₁=C₂V₂ to answer the following questions (remember to give both solvent and solute answers) Answer questions 6-8 using the following information: You are told to make 400 mL of a 1 M solution from a 4 M solution. 5. What is the missing variable? Use the equation to solve for it. (2 pts) VI:100mL
Per course policy on academic honesty, reproduction or dissemination of this document is prohibited. 8. Calculate the molarity of the following solution: 20.0 g KC in 400 mL solution? (MW 73.50 g/mol). Hint: if you dissolved 73.50 g/mol of the KCI into 1 L, then the Molarity would be 1 M. (3 pts) 9. If I dilute 300 mL of 2 M lithium acetate solution to a volume of 600 mL, what will the concentration of this solution be? (2 pts)