Run #9 Run Ho Rin #11 Part 1-Determination of the Rate Law: time (s) Rate* (¹¹) 5 Trial 6 1 Rate is defined as 7 2 8 3 T

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Run 9 Run Ho Rin 11 Part 1 Determination Of The Rate Law Time S Rate 5 Trial 6 1 Rate Is Defined As 7 2 8 3 T 1 (57.34 KiB) Viewed 87 times

Run 9 Run Ho Rin 11 Part 1 Determination Of The Rate Law Time S Rate 5 Trial 6 1 Rate Is Defined As 7 2 8 3 T 2 (15.05 KiB) Viewed 87 times

Run 9 Run Ho Rin 11 Part 1 Determination Of The Rate Law Time S Rate 5 Trial 6 1 Rate Is Defined As 7 2 8 3 T 3 (32.66 KiB) Viewed 87 times

Run 9 Run Ho Rin 11 Part 1 Determination Of The Rate Law Time S Rate 5 Trial 6 1 Rate Is Defined As 7 2 8 3 T 4 (29.26 KiB) Viewed 87 times

Run 9 Run Ho Rin 11 Part 1 Determination Of The Rate Law Time S Rate 5 Trial 6 1 Rate Is Defined As 7 2 8 3 T 5 (41.27 KiB) Viewed 87 times

Run #9 Run Ho Rin #11 Part 1-Determination of the Rate Law: time (s) Rate* (¹¹) 5 Trial 6 1 Rate is defined as 7 2 8 3 Trial 4 902 35 s 205 405 AA At Part 2-Determination of the Activation Energy: T (K) time (s) ** Rate is defined as 0.80 Temperature (°C) 59% 40°C 70°c 0 °C ΔΑ At 0-0022 31 -obag 332 K 0-100 [BrO;'] (M) 0.0124 0.02M 0.006M 0-00575 0-02/M 0-02M 0-00 6M 0-016 0-012M 0-OMM 0-006M 0.005 0.012M 0.02M 0-0121 where time is how long it takes for the absorbance to increase from 0.60 to 0.80 255 0-0300 [H'] (M) Rate** 0.008 (M) -(K) In(Rate) Rate=20 0.00301-4-83 6-606 0.00319-5-12 313K 35; 343к 55 0.04 0.0029 -3-22 273K 210, 0.00095 0·0036-696 where time is how long it takes for the absorbance to increase from 0.60 to
Part 3-The Effect of a Catalyst: Time it took for the mixture to react from A = 0.600 to 0.800 when a catalyst was added to the reactants.
Calculations: Part 1-Determination of the Rate Law: Write the rate laws for both Trials 1 and 2 below making sure to include the rates and concentrations of each reactant that you calculated in the table above. Don't forget the exponents a, b, and c, since you will be solving for those using this data. For Trial 2 For Trial 1 Now divide the rate expression for Trial 2 by that for Trial 1 and simplify. Now solve for a, and round this to the nearest whole number. a= Use Trials 1 and 3 to determine b, and Trials 1 and 4 to determine c. Show your calculations below.
Calculate the rate constant, k, by using the orders, a, b, and c, that you calculated above, the rate and concentration data from Trial 1. Remember that a rate constant must have units. k= Write the full rate law for the reaction below including all the numbers you just calculated.
2-Determination Part Use Microsoft Excel to plot In(Rate) vs. 7 Have Excel draw a best-fit line through the points and determine the slope of the line. Use the slope to determine the activation energy (E₁) for the reaction. Make sure you turn in your spreadsheet and graph with the lab report. of the Activation Energy: Slope= Show your calculations for Ea. E₁= Part 3-The Effect of a Catalyst: Describe the effect of a catalyst below. Use the rate you observed to back your description Questions: 1) By what factor would the rate of reaction increase if you doubled [H+] and increased the temperature of the reaction by 10°C at the same time? Explain your answer.