Given the thermochemical equations X₂ + 3Y₂ → 2XY, AH₁ = -370 kJ X₂ +2Z₂ → 2XZ₂ AH₂ = -140 kJ 2Y₂+Z₂2Y₂Z AH₂ = -220 kJ C
Posted: Thu Jun 30, 2022 6:24 pm
Given the thermochemical equations X₂ + 3Y₂ → 2XY, AH₁ = -370 kJ X₂ +2Z₂ → 2XZ₂ AH₂ = -140 kJ 2Y₂+Z₂2Y₂Z AH₂ = -220 kJ Calculate the change in enthalpy for the reaction. 4XY, +7Z₂6Y₂Z + 4 XZ₂ AH = -120 Incorrect kJ