Given the thermochemical equations X₂ + 3Y₂ → 2XY, AH₁ = -370 kJ X₂ +2Z₂ → 2XZ₂ AH₂ = -140 kJ 2Y₂+Z₂2Y₂Z AH₂ = -220 kJ C

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answerhappygod
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Given the thermochemical equations X₂ + 3Y₂ → 2XY, AH₁ = -370 kJ X₂ +2Z₂ → 2XZ₂ AH₂ = -140 kJ 2Y₂+Z₂2Y₂Z AH₂ = -220 kJ C

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Given The Thermochemical Equations X 3y 2xy Ah 370 Kj X 2z 2xz Ah 140 Kj 2y Z 2y Z Ah 220 Kj C 1
Given The Thermochemical Equations X 3y 2xy Ah 370 Kj X 2z 2xz Ah 140 Kj 2y Z 2y Z Ah 220 Kj C 1 (16.97 KiB) Viewed 76 times
Given the thermochemical equations X₂ + 3Y₂ → 2XY, AH₁ = -370 kJ X₂ +2Z₂ → 2XZ₂ AH₂ = -140 kJ 2Y₂+Z₂2Y₂Z AH₂ = -220 kJ Calculate the change in enthalpy for the reaction. 4XY, +7Z₂6Y₂Z + 4 XZ₂ AH = -120 Incorrect kJ
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