4. A chemistry 1411 student mixed 25 grams of Fe with 40 grams of H:O. The balanced equation for this reaction is An 95%

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4 A Chemistry 1411 Student Mixed 25 Grams Of Fe With 40 Grams Of H O The Balanced Equation For This Reaction Is An 95 1 (47.64 KiB) Viewed 60 times

4. A chemistry 1411 student mixed 25 grams of Fe with 40 grams of H:O. The balanced equation for this reaction is An 95% yield of Fe3O4 was obtained. a) 3Fe(s) + 4H₂O(1)→ Fe3O.(s) + H2(g) 40g H₂0 x 1m61 H20 What is the theoretical yield of FesO? 15 Points 9) 15 Points X 15.0169100 4 mol H₂O b) What is the limiting reactant in this experiment? Fe grams (5 points) 3mxLFL 55.855 Fe = 83.75fe neaded we have 25g therefore FR is the limiting reactant Reactants General Reaction Type Molecular Equation Complete Ionic Equation Net Ionic Equation Evidence of Reaction c) What is the actual yield of FesO, if the reaction gave a 95% yield? Reactants General Reaction Type Molecular Equation Complete Ionic Equation Net Ionic Equation Evidence of Reaction (2 points) Zinc metal hydroiodic acid grams (3 points) Mercury(II) nitrate solution Sodium Sulfide solution