Question 2 Compound A, C5H10, is reacted with Br₂ in H₂O. The product is then reacted with acetylide anion, C₂H, followe

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

Question 2 Compound A, C5H10, is reacted with Br₂ in H₂O. The product is then reacted with acetylide anion, C₂H, followe

Post by answerhappygod »

Question 2 Compound A C5h10 Is Reacted With Br In H O The Product Is Then Reacted With Acetylide Anion C H Followe 1
Question 2 Compound A C5h10 Is Reacted With Br In H O The Product Is Then Reacted With Acetylide Anion C H Followe 1 (43.36 KiB) Viewed 85 times
Question 2 Compound A, C5H10, is reacted with Br₂ in H₂O. The product is then reacted with acetylide anion, C₂H, followed by Lindlar's catalyst. The resulting alkene is reacted with BHs followed by NaOH and hydrogen peroxide and finally Jones reagent to give final Compound B, C7H₁4O3. Using the provided spectral data, draw the structure of B and label all provided spectral data. You may show the intermediate products for partial credit. NOTE: Ignore the side reaction that occurs in step 2. You don't know the reaction that would prevent it so I didn't include it. IR (cm³): 2745 & 1679 CsH10 Compound A 13CNMR (ppm, splitting): 132, s; 119, d; 26, q; 17, q; 13, q 1¹HNMR (ppm): 5.19, 1H, q: 1.64, 6H, s; 1.56, 3H, d 1. Br₂/H₂O 2.:0 3. Lindlar's cat. 4. BH₂ 5.H₂O₂, NaOH 6. Jones reagent C7H1403 Compound B IR (cm:¹): 3200 (broad), 1712 (strong) 13CNMR (ppm, DEPT): 179/none; 77/none; 42/same; 35/invert; 27/same; 8/same ¹HNMR (ppm): 11.8, 1H, s (exchanges w/ D₂O); 4.5, 1H, s (exchanges with D₂O); 2.1, 2H, d; 1.7, 1H, sextet; 1.2, 6H, s; 0.9, 3H, d
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply