What is the equilibrium expression for this reaction? 2 NO(g) + O₂(g) → 2NO₂(g) Ок K K K OK = = = = = [2 NO₂] [2 NO] [0₂

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What is the equilibrium expression for this reaction? 2 NO(g) + O₂(g) → 2NO₂(g) Ок K K K OK = = = = = [2 NO₂] [2 NO] [0₂

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What is the equilibrium expression for this reaction? 2 NO(g) + O₂(g) → 2NO₂(g) Ок K K K OK = = = = = [2 NO₂] [2 NO] [0₂] [2 NO₂]² [2 NO]² [0₂] [NO₂] 2 [NO]² [0₂] [NO]² [0₂] [NO₂]² [2 NO]² [0₂] [2 NO₂]²
Question 5 (3 points) The equilibrium constant for a certain reaction is K = 1.8 x 10-5. What does K, the equilibrium constant, allow you to conclude about the reaction? It is product-favored meaning that a majority of the reactants form products. It must be an oxidation-reduction reaction because the value of K is so small. It must be an acid-base reaction because the value of K is so small. It is reactant-favored meaning that a majority of the reactants do not form products.
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