Example 6. A running dog leaps with initial velocity of 11 m/s at 30°. What is the range? Draw figure and Voy = 11 sin 3

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Example 6 A Running Dog Leaps With Initial Velocity Of 11 M S At 30 What Is The Range Draw Figure And Voy 11 Sin 3 1 (1.25 MiB) Viewed 56 times

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Example 6. A running dog leaps with initial velocity of 11 m/s at 30°. What is the range? Draw figure and Voy = 11 sin 300 find components: = 11 m/s Vox = 9.53 m/s CO=30 Voy = 5.50 m/s = 11 cos 300 sav OX = To find range, first find twhen y = 0; a = -9.8 m/s2 y=v,,t +ļ atº; 0 = (5.50)t +}(-9.8)? = יוס 4.9 +2 = 5.50 t 5.50 m/s t= t= 1.12 s 4.9 t = 5.50 4.9 m/s2

Example 6 (Cont.) A dog leaps with initial velocity of 11 m/s at 300. What is the range? Range is found Voy = 10 sin 31 from x-component: V = 10 m/s Vx= Vox = 9.53 m/s A =31° x = vxt; t = 1.12 s Vox = 10 cos 310 = OX Horizontal velocity is constant: Vy = 9.53 m/s x = (9.53 m/s)(1.12 s) = 10.7 m = X = Range: x= 10.7 m