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The ECG Lead III signal is determined by subtracting the left arm (LL) from the right arm (LA) unipolar limb leads (Lead
Posted: Mon Mar 21, 2022 5:02 pm
by answerhappygod
- The Ecg Lead Iii Signal Is Determined By Subtracting The Left Arm Ll From The Right Arm La Unipolar Limb Leads Lead 1 (448.94 KiB) Viewed 36 times
The ECG Lead III signal is determined by subtracting the left arm (LL) from the right arm (LA) unipolar limb leads (Lead 10 = LL - LA). At the same time the resulting Lead III signal needs to be scaled by a factor of 10 (Av = 10). If Ri= 10 k0, determine values of R2, R3 and R4 in the op-amp based circuit shown below, in order to produce the required output operation. Bu R, LA 11 Ri V.= Lead III LL iz RA