= = 1. Consider a 0.45um wide silicon ring with a ng = 4.205 and Neff = 2.45 at 1550nm and a FSR = 3.2nm at normal tempe

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answerhappygod
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= = 1. Consider a 0.45um wide silicon ring with a ng = 4.205 and Neff = 2.45 at 1550nm and a FSR = 3.2nm at normal tempe

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1 Consider A 0 45um Wide Silicon Ring With A Ng 4 205 And Neff 2 45 At 1550nm And A Fsr 3 2nm At Normal Tempe 1
1 Consider A 0 45um Wide Silicon Ring With A Ng 4 205 And Neff 2 45 At 1550nm And A Fsr 3 2nm At Normal Tempe 1 (330.83 KiB) Viewed 35 times
= = 1. Consider a 0.45um wide silicon ring with a ng = 4.205 and Neff = 2.45 at 1550nm and a FSR = 3.2nm at normal temperature 300K. Please calculate the designed radius of the ring resonator and the nearest resonance peak around 1550nm. If the refractive index of silicon varies with temperature is linear, dn/dT = 2x10^4 /K. Please calculate the temperature should be raised needed to hit one peak to 1550nm. [20 marks] (Hint ng = neff – 1*dneff/d), and consider that Neff varies with a linearly. And temperature raising have no influence on group index ) =
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