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How does the value of Ka you calculated (3.67x10^-6) compare with the literature value (Ka = 8.0 × 10-5)? What is the pe

Posted: Thu Mar 17, 2022 11:32 am
by answerhappygod
How does the value of Ka you calculated
(3.67x10^-6) compare with the literature value (Ka = 8.0 ×
10-5)? What is the
percent error of this value? (got percent error by using the
equation: |experimental value - literature value| / literature
value = 95%) What does that percent indicate?