How does the value of Ka you calculated
(3.67x10^-6) compare with the literature value (Ka = 8.0 ×
10-5)? What is the
percent error of this value? (got percent error by using the
equation: |experimental value - literature value| / literature
value = 95%) What does that percent indicate?
How does the value of Ka you calculated (3.67x10^-6) compare with the literature value (Ka = 8.0 × 10-5)? What is the pe
-
- Site Admin
- Posts: 899603
- Joined: Mon Aug 02, 2021 8:13 am