35. In Fig. 9.47, a long, straight conductor perpendicular to the plane of the paper carries an electric current i. A ba

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35. In Fig. 9.47, a long, straight conductor perpendicular to the plane of the paper carries an electric current i. A ba

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35 In Fig 9 47 A Long Straight Conductor Perpendicular To The Plane Of The Paper Carries An Electric Current I A Ba 1
35 In Fig 9 47 A Long Straight Conductor Perpendicular To The Plane Of The Paper Carries An Electric Current I A Ba 1 (64.82 KiB) Viewed 74 times
35. In Fig. 9.47, a long, straight conductor perpendicular to the plane of the paper carries an electric current i. A bar magnet having poles of strength m lies in the plane of the paper. The vectors H, Hy, and Hs represent the components of the magnetic intensity H due to the current and to the N and S poles of the magnet, respec- tively. The magnitudes of the components of H are given by 1 m H; 1 i 2πα HN 1 m 4т 2 HS 41 c2 Given that a=0.300 m, b = 0.400 m, c = 0.300 m, the length of the magnet is 0.500 m, i = 4.00 A, and m = 2.00 A. m, calculate the resultant magnetic intensity H. The component H, is parallel to the magnet. Hint Solve the missing angle first IN [ m a 제 H HN S m Fig. 9.47 H
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