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The forces, in members DG and Fl of the truss shown below, has been calculated using the method of sections 5 KN А B TA 3 m 5 KN F D a a 3 m 5 KN ІН 1 G b b 3 m K 2 m 2 m
5 KN K 3m 5 KN D F FDG EDE EEF FFL 4m = = Mp = 0: FdG(4 m)-(5 kN)(3 m) = 0 ... FDG = +3.75 kN Fy = 0:-3.75 kN - FFI = 0 FEI = -3.75 kN = a) When two (or more) members are connected by a pin, it is does not matter in which member the pin is taken. However, it is considered more efficient to to take the pin as part of a multi-force member. Discuss this in the context of the truss in this question. [2 Marks]
= = Mp = 0: FDG(4 m) -(5 kN)(3 m) = 0 FDG = +3.75 kN Fy = 0: -3.75 kN - FFI = 0 Fri = -3.75 kN a) When two (or more) members are connected by a pin, it is does not matter in which member the pin is taken. However, it is considered more efficient to to take the pin as part of a multi-force member. Discuss this in the context of the truss in this question. [2 Marks] b) Using diagrams, and compulsorily in your own words, explain why is the action of constraint at J (in reality a gusset plate, idealized as a smooth pin joint) on members JH, JG and JK modelled as only a force? In other words, why is the gusset plate joint not modeled as a rough pin joint? [4 Marks] c) Using a diagram (compulsory!), point out the number of b rigid bars which are connected at j joints with c foundation constraints, in this truss. (Please mark joints and bars with arrow) (1+1+2 marks] (Upload answer of this question in a single pdf file)