- A 2 250 Kg Pile Driver Is Used To Drive A Steel I Beam Into The Ground The Pile Driver Falls 3 70 M Before Coming Into 1 (14.62 KiB) Viewed 45 times
- A 2 250 Kg Pile Driver Is Used To Drive A Steel I Beam Into The Ground The Pile Driver Falls 3 70 M Before Coming Into 2 (54.84 KiB) Viewed 45 times
beam = my Consider the work done on the pile driver from the time it starts from rest until it comes to rest at the end of the fall. From the work-kinetic energy theorem, we have the following equation w = AK = W gravity + W - 2 mv, ? - 1 mu? Let d represent the distance over which the driver Falls freely, and let h represent the distance it moves the piling. So we know that the driver falls vertically for a total height of h + d. We also know that the pile driver starts from rest and ends at rest, that is, we know that v = V1 = 0. We have the following equations, where Fis the average force Woravity - (mg)Ch + d) cos 0 Wbcam - ()h) cos 180° The angles are 09 and 180° because the weight vector is in the direction of motion and the beam exerts a force on the driver in the opposite direction. Substituting in the equation derived from the work-kinetic energy theorem, we have (mg)th + d) -(F) h) = 0. Solving for the average force, we have the following. (mg) (htung) F = |kg 9.80 m/s) h m m * 105N The force on the pile driver is O upward. downward.