1) (C18H100). The compound contains two phenyl groups (CH) 7double bords (a) DBE_9 DBE.C+1-(1/2) = 16+1 -1672-17-8-9 - (

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1 C18h100 The Compound Contains Two Phenyl Groups Ch 7double Bords A Dbe 9 Dbe C 1 1 2 16 1 1672 17 8 9 1 (333.21 KiB) Viewed 55 times

1) (C18H100). The compound contains two phenyl groups (CH) 7double bords (a) DBE_9 DBE.C+1-(1/2) = 16+1 -1672-17-8-9 - (b) Analyze each region of the proton NMR spectrum, draw part structures. Use the format: 8 1.23 (dq, J = 9,7 Hz. 1H). 1-28 38 4-58 6-78 7-8 8 (c) Interpret key signals in the 13C NMR spectra. The top spectrum is coupled, the bottom is noise proton decoupled. Do not attempt to make a detailed assignment to the signals between 8 125 and 8 135. The expansion provided is for your information only (d) Draw the structure of the compound. ОН cas

1) (C16H160) 270 MHz 'H NMR Spectrum in CDCh (Source: J. W Ringer/Reich 11/17) 2.9 2.8 2.7 6.6 6.5 6.3 6.2 4.5 4.4 Please call this a multiplet 10.64 2.00 1.96 1.00 8.5 8.0 7.5 7.0 6.5 6.0 5.5 5.0 4.5 3.5 3.0 2.5 2.0 1.5 1.0 0.5 0.0 4.0 ppm

1500 1000 3500 3000 2000 2500 while 1) (C16H160) 125 MHz 13C NMR Spectrum in CDCI , (Source: J. W. Ringer/Reich 11/17) 130 132 131 129 128 127 126 Fully coupled TMS 60 40 20 0 100 80 200 180 140 120 160 1 1 Proton decoupled 131 130 129 128 127 126 TMS 140 180 160 120 200 100 80 60 40 20 0