Two non-conducting spheres have equal and opposite charges of magnitude 360 uC and are place on opposite sides of a circ

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

Two non-conducting spheres have equal and opposite charges of magnitude 360 uC and are place on opposite sides of a circ

Post by answerhappygod »

Two Non Conducting Spheres Have Equal And Opposite Charges Of Magnitude 360 Uc And Are Place On Opposite Sides Of A Circ 1
Two Non Conducting Spheres Have Equal And Opposite Charges Of Magnitude 360 Uc And Are Place On Opposite Sides Of A Circ 1 (166.45 KiB) Viewed 52 times
Two Non Conducting Spheres Have Equal And Opposite Charges Of Magnitude 360 Uc And Are Place On Opposite Sides Of A Circ 2
Two Non Conducting Spheres Have Equal And Opposite Charges Of Magnitude 360 Uc And Are Place On Opposite Sides Of A Circ 2 (102.68 KiB) Viewed 52 times
help solve 20
Two non-conducting spheres have equal and opposite charges of magnitude 360 uC and are place on opposite sides of a circle that lies in the horizontal xy- plane, as shown in the diagram. The circle has a diameter of 50cm Final Position Initial Position
A third charge of Q - 20 C is placed at the bottom of the circle, and is then moved to the top of the circle. What is the net work required to move charge Q. and does the path taken by Q matter? ZERO J & Yes, the charge must travel directly up. 130 ) & No, the path taken doesn't matter. 92) & No, the path taken doesn't matter. ZERO J & No, the path taken doesn't matter. (92) & Yes, the charge must travel directly up.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply