P 1445 45 degree Fig. 2 As shown in Fig. 2, a beam is clamped on one end. The diameter of the cross section is r. m and

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P 1445 45 Degree Fig 2 As Shown In Fig 2 A Beam Is Clamped On One End The Diameter Of The Cross Section Is R M And 1 (36.04 KiB) Viewed 43 times

P 1445 45 degree Fig. 2 As shown in Fig. 2, a beam is clamped on one end. The diameter of the cross section is r. m and the length of the beam is /m. Young's modulus is given by E and Poisson's ratio is v. The energy equations due to bending, transverse & axial load are given by M UM dx 2E1 where M is moment applied and I is the moment of inertia, PP dx 2E4 U. = ( A where P is an axial load, E is Young's modulus and A is the cross-sectional area. -dx 2GA where Vis shear force, K is shear correction factor, and G is shear modulus. a) Find the strain energy in the beam due to bending, transverse shear, and axial load. (10 points) b) Discuss the strain energy due to transverse shear when the ratio between r and lis very small. (5 points) c) Calculate the displacements in x & y directions at the tip of the beam. (10 points)