1.85 atm of CO (8) and 0.225 atm of H2O(g) were added to an otherwise empty vessel. The reaction shown below was left un

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answerhappygod
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1.85 atm of CO (8) and 0.225 atm of H2O(g) were added to an otherwise empty vessel. The reaction shown below was left un

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1 85 Atm Of Co 8 And 0 225 Atm Of H2o G Were Added To An Otherwise Empty Vessel The Reaction Shown Below Was Left Un 1
1 85 Atm Of Co 8 And 0 225 Atm Of H2o G Were Added To An Otherwise Empty Vessel The Reaction Shown Below Was Left Un 1 (52.15 KiB) Viewed 46 times
1 85 Atm Of Co 8 And 0 225 Atm Of H2o G Were Added To An Otherwise Empty Vessel The Reaction Shown Below Was Left Un 2
1 85 Atm Of Co 8 And 0 225 Atm Of H2o G Were Added To An Otherwise Empty Vessel The Reaction Shown Below Was Left Un 2 (28.7 KiB) Viewed 46 times
1.85 atm of CO (8) and 0.225 atm of H2O(g) were added to an otherwise empty vessel. The reaction shown below was left until it reached equilibrium. Note that the equilibrium constant, Ky, at 150°C is 0.675 CO(g) + H2O(g) – CO2(g) + H2 (8) a) Based on the information provided above, fill in the ICE table below inputting x for any relative changes. Be sure to indicate the direction of change, i.e. +/- Be sure to use the proper number of significant figures. Any zeroes should be denoted as 0. The equilibrium row should contain the x variable. CO (8) + H2O(g) + CO2(g) + H2 (8) 1 С E b) Determine the value of x from the previous question I atm c) Determine the partial pressures of each of the reactants and products when the system reaches equilibrium Pco: atm PHO: atm

c) Determine the partial pressures of each of the reactants and products when the system reaches equilibrium Poo: atm PH.0: atm Pco, atm Рн. atm d) From the information provided in the question, determine the value of AG (in kJ/mol) for the reaction at 150°C. I AG: kJ/mol
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