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MCQ 1.3.2 GATE 2010 If A = xya, + zľa,, then f A. dl over the path shown in the figure is Y 4 3+ 1- С 0 1/3 2/13 (A) 0 (
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MCQ 1.3.2 GATE 2010 If A = xya, + zľa,, then f A. dl over the path shown in the figure is Y 4 3+ 1- С 0 1/3 2/13 (A) 0 (
MCQ 1.3.2 GATE 2010 If A = xya, + zľa,, then f A. dl over the path shown in the figure is Y 4 3+ 1- С 0 1/3 2/13 (A) 0 (C) 1 (B) ✓3 (D) 2/3
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