Ci = 101 C2 -- 6-841 -10 =1:1 0 1 0 0 0 C3 = 1 0 0 0 C4 = 0 1 0 0 1 0 0 1 0 1 0 0 1 0 The matrices there have l's just a

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Ci 101 C2 6 841 10 1 1 0 1 0 0 0 C3 1 0 0 0 C4 0 1 0 0 1 0 0 1 0 1 0 0 1 0 The Matrices There Have L S Just A 1 (30.26 KiB) Viewed 37 times

Ci = 101 C2 -- 6-841 -10 =1:1 0 1 0 0 0 C3 = 1 0 0 0 C4 = 0 1 0 0 1 0 0 1 0 1 0 0 1 0 The matrices there have l's just above and below the main diagonal. Going down the matrix, which order of columns (if any) gives all l's? Explain why that permutation is even for n = 4,8,12,... and odd for n = 2, 6, 10, .... Then Cn = -1 (n = 2,6,...). Ch = 0 (odd n) Cn = 1 (n = 4,8,...) Please don't copy the manual solution of the book.