solve the equations (a) log5(3𝑥 βˆ’ 4) = 1 (b) ln(𝑥 + 5) + ln(𝑥 βˆ’ 2) = ln 6𝑥

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answerhappygod
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solve the equations (a) log5(3𝑥 βˆ’ 4) = 1 (b) ln(𝑥 + 5) + ln(𝑥 βˆ’ 2) = ln 6𝑥

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solve the equations (a) log5(3π‘₯ βˆ’ 4) = 1
(b) ln(π‘₯ + 5) + ln(π‘₯ βˆ’ 2) = ln 6π‘₯
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