Ammonia gas can be prepared by the reaction CaO(s) + 2NH4Cl(s) + 2NH3(g) + H2O(g) +CaCl(s) If 101 g Cao reacts with 199
Posted: Thu Feb 17, 2022 11:12 am
Ammonia gas can be prepared by the reaction CaO(s) + 2NH4Cl(s) + 2NH3(g) + H2O(g) +CaCl(s) If 101 g Cao reacts with 199 g NH4Cl, how many moles of reactants and products are there when the reaction is complete? 9 mol of are not consumed in excess). mol of NH3 mol of H2O mol of CaCl2