Ammonia gas can be prepared by the reaction CaO(s) + 2NH4Cl(s) + 2NH3(g) + H2O(g) +CaCl(s) If 101 g Cao reacts with 199

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Ammonia gas can be prepared by the reaction CaO(s) + 2NH4Cl(s) + 2NH3(g) + H2O(g) +CaCl(s) If 101 g Cao reacts with 199

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Ammonia Gas Can Be Prepared By The Reaction Cao S 2nh4cl S 2nh3 G H2o G Cacl S If 101 G Cao Reacts With 199 1
Ammonia Gas Can Be Prepared By The Reaction Cao S 2nh4cl S 2nh3 G H2o G Cacl S If 101 G Cao Reacts With 199 1 (23.47 KiB) Viewed 30 times
Ammonia gas can be prepared by the reaction CaO(s) + 2NH4Cl(s) + 2NH3(g) + H2O(g) +CaCl(s) If 101 g Cao reacts with 199 g NH4Cl, how many moles of reactants and products are there when the reaction is complete? 9 mol of are not consumed in excess). mol of NH3 mol of H2O mol of CaCl2
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