Calculate the energy difference (in kJ mol-') between light of 2 = 200 nm and 2 = 600 nm. Calculate the factor in this equation: E (kcal mol-') Factor 2 (nm) What is the temperature in degree Celsius (°C) required to achieve 1% population of the 1st excited state if AE = 240 kJ mol-1?
DE- uc ( 22 - 11 ) Еа ис A = loonm =boum DE= E, E = uc nc da , 6.6x1033x13 Hoo x 10) ) Qooy boo X1018 DE 6.6x10T 6) factor od=450nm E(kealmot) a Factor tamm) DE 6-6x108 5 = 1.571x10 Calmol =1571x10 kalfood ruol 1.571x103 = factor 400 628.722 x 10² factor - DEIRET nexcited nground ng - 240 x 10 natt 2-0) e B 314XT - 4.6051 - 240x1000 8.3121 XT 6 268.47k 5995, 470 .
Calculate the energy difference (in kJ mol-') between light of 2 = 200 nm and 2 = 600 nm. Calculate the factor in this e
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Calculate the energy difference (in kJ mol-') between light of 2 = 200 nm and 2 = 600 nm. Calculate the factor in this e
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