Experiment V: Active Filter 470 K 10K 10k 0.0940F 470F HE 47F HE C1 RI to scope CH2 0.1UF 47K VO w 22K to scobe CH1 Mate

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answerhappygod
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Experiment V: Active Filter 470 K 10K 10k 0.0940F 470F HE 47F HE C1 RI to scope CH2 0.1UF 47K VO w 22K to scobe CH1 Mate

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Experiment V Active Filter 470 K 10k 10k 0 0940f 470f He 47f He C1 Ri To Scope Ch2 0 1uf 47k Vo W 22k To Scobe Ch1 Mate 1
Experiment V Active Filter 470 K 10k 10k 0 0940f 470f He 47f He C1 Ri To Scope Ch2 0 1uf 47k Vo W 22k To Scobe Ch1 Mate 1 (487.11 KiB) Viewed 54 times
Experiment V Active Filter 470 K 10k 10k 0 0940f 470f He 47f He C1 Ri To Scope Ch2 0 1uf 47k Vo W 22k To Scobe Ch1 Mate 2
Experiment V Active Filter 470 K 10k 10k 0 0940f 470f He 47f He C1 Ri To Scope Ch2 0 1uf 47k Vo W 22k To Scobe Ch1 Mate 2 (131.62 KiB) Viewed 54 times
Experiment V: Active Filter 470 K 10K 10k 0.0940F 470F HE 47F HE C1 RI to scope CH2 0.1UF 47K VO w 22K to scobe CH1 Materials Required: 1) 741CP op-amp, 2) 2x10 KO resistors, 5 KQ resistor, 47 K resistor, 470 KO resistor, 22 KN resistor, 2x 47nF, 2x0.1 uF. 3) Dual channel oscilloscope, 4) Function generator, 5) DC power supply, board and cables. Calculations: For the circuit below, the similar relationships as in the passive filter design are valid: w 470 K R R w 2C С HH R/2 R1 TO 2R VO HS
1 fo f. BW = fu - fu, Q = A,(at f.) 470K2 = 10. 47K12 2ntRC BW' Procedure: 1. Build the circuit. The signal source is taken directly from the sine wave output of the function generator. 2. Fill in the Table below: Measured Gain (Vo/Vin) Pololo soliclo X lo 0.7 10.8 0.9 1.0 1.1 1.2 1.3 3. Find: fu = ... ? fi = ... ? BW = ... ? Q = ...?
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