na12u - 11, M: 05, Hi>5. P-value = P/s>5,4/= 5) = P(chi>11x5.42/52) = P(chi2>12.8304) = 1 - P(chi2<12.8304) From the tab

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Na12u 11 M 05 Hi 5 P Value P S 5 4 5 P Chi 11x5 42 52 P Chi2 12 8304 1 P Chi2 12 8304 From The Tab 1 (21.57 KiB) Viewed 59 times

na12u - 11, M: 05, Hi>5. P-value = P/s>5,4/= 5) = P(chi>11x5.42/52) = P(chi2>12.8304) = 1 - P(chi2<12.8304) From the tables, chi2cdf(12.83,11) = 0.695 p-vale = 1 -0.695 = 0.305. The P-value is not significant, so this does not strongly suggest that a > 5mm How strongly does this suggest that the population standard deviation is greater than 5 mm? check this a sample of 12 tomatoes is measured and found to have a sample standard deviation of 5.4 mm. Q. The size of tomatoes in a large population is required to have a standard deviation of less than 5 mm. To