(1 point) Life rating in Greece - Greece faced a severe economic crisis since the end of 2009. Suppose a Gallup poll sur
-
- Site Admin
- Posts: 899603
- Joined: Mon Aug 02, 2021 8:13 am
(1 point) Life rating in Greece - Greece faced a severe economic crisis since the end of 2009. Suppose a Gallup poll sur
question, and calculate a 95% confidence interval for the proportion of Greeks today who say they are "suffering" with a margin of error of no more than 4.25%. What size sample should we take? Important! Use the information from the 2011 sample for a planning value for p* and round your z* value to EXACTLY 3 decimal places. Your answer should be given as an integer. n =
(1 point) Life rating in Greece - Greece faced a severe economic crisis since the end of 2009. Suppose a Gallup poll surveyed 1100 randomly sampled Greeks in 2011 and found that 264 of them said they would rate their lives poorly enough to be considered "suffering." Round all answers to four decimal places. 1. What is the population parameter of interest? OA. The 264 Greeks in the sample who believed they were suffering. OB. All the people who lived in Greece in 2011. C. The actual proportion of Greeks who said they were suffering in 2011. D. The score on the survey that corresponds to suffering. 2. What is the value of the point estimate of this parameter? P= 3. Use the sample information from 2011 to construct a 95% confidence interval for the proportion of Greeks in 2011 who said they were "suffering." 4. If we decided to use a higher confidence level, the confidence interval would be: A narrower B. wider C. stay the same 5. If we used the same confidence level with a larger sample, the confidence interval would be: O A narrower B. wider C. stay the same 6. The sample information from 2011 gives a standard error of SEK = 0.0129. Which of the statements below is a correct interpretation of the standard error? OA. There is a 1.29% chance the sample proportion we calculated is the same as the true population proportion. B. If we had taken many samples of size n = 1100 from the population in 2011, we would expect any of those sample proportions to be approximately 0.0129 from the true population proportion, on average. OC. We can be 1.29% confident that our margin of error is approximately correct. OD. We have strong evidence that the true proportion of people who said they were suffering in 2011 is within the 95% confidence interval. 7. Suppose we wanted to take a new sample of Greeks today, ask them the same